sin(A) - sin(B) Trig Identity Derivation

sin(A) - sin(B) Trig Identity Derivation

Cowan Academy

4 месяца назад

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How to prove the trigonometric identity:
sin(A) - sin(B) = 2cos[(A + B) / 2]sin[(A - B) / 2]

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#sin(A)-sin(B)
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