Комментарии:
Thanks mate. Great video.
ОтветитьBrilliant
ОтветитьDoes this explain why it doesn't work when the height of outer pipe is higher than the height of water in the tank?
ОтветитьNice.. Thank you
ОтветитьYoure the worst
Ответитьwhy siphone bell siphone and heron fountain become a perpetual source of energy by applyeing some little pressure or extra effort so we got more energy by applyeing littele energy since potential energy of atmosphere is never ending forever
ОтветитьVery concise and the explanation is on point.
ОтветитьBrilliant.
ОтветитьYOu are creating a new education revolution
ОтветитьWell said
ОтветитьThat was so incredibly concise. Thanks man!
Ответитьmfr’s hitting pause in episode 4 trying to figure this shit out
ОтветитьI have a question; you repeatedly state that there has to be no air in the pipe. How does this relate to flying droplet siphons? There is clearly air inbetween two water pipes.
ОтветитьAnnoying .. keep your pen caps OFF !
ОтветитьHow would you explain that silphons also work in vacuum?
Ответитьpretty bad man, pretty bad
ОтветитьHello.. I want to ask.. Can the water increase its pressure when u make an tube arc that ishigher.
Imagine when 3 floors.
1st floor is the the outlet.
2nd floor is the water jug(source of water)
And 3rd is the water arc of the water pipe
We all know that we can directly get water from the source in the 2nd floor directly to the 1st floor..
The question is.. If we increase the height of the tupe upto the 3rd floor. It will increase?
I understand what you have said but it appears the explanation does not explain why the outlet of the pipe needs to be at a level lower than the water level. (Or maybe I have missed something?)
Ответить🙂
ОтветитьFinally understood this. Thanks for the video!
ОтветитьA good explanation but would disagree on a couple of points.
Firstly the vacuum wouldn't need to be perfect. If you connected a transparent vacuum chamber at the top with a larger volume than the section of tubing you would see the water from the top bucket pulled (or more accurately, pushed) up, accumulate at the bottom of the vacuum chamber and flow back down again. The section of "air" at the top of the vacuum chamber would have to remain below 1 atm enough for the atm at the surface of the top bucket to push water into the chamber. The mass of the height of the column of water going to the bottom bucket (along with gravity) preserves the vacuum below 1 atm.
The second point follows from the first in that the partial vacuum and water at the top section of the tube can be separated but this can never happen with just the tube itself but requires a separate break section with greater volume than the rest of the tube.
Stop clicking the pen lids on and off its very annoying!
ОтветитьI got absolutely blasted off some Zaza and looked this up thanks for the explanation
ОтветитьShow how much energy we got by siphon at maximum level
Stp and ntp
Siphon under high or low pressure created more energy efficient???
Well explained.
ОтветитьI'm only watching because literally every series of taskmaster they try this and no one has yet to succeed.
ОтветитьIs the height from one body of water to another the cause of the vacuum strength for the suction or is it gravity
ОтветитьHi and thanks for the video, but I have a question. Let's imagine a straight pipe from the tank, with a turn at 90 °, then a straight horizontal section of pipe, another turn toward the bottom at 90 ° again, and finally a straight vertical section of the pipe. I made the hypothesis that at the initial condition, the fluid in the pipe is at rest. So, I calculate the pressure at the inlet of the pipe into the tank Pe = rho * g * (Za + H - Ze) + Pair (where Za is the free surface altitude, Ze the altitude of the inlet of the pipe, and H is the distance between the free surface and the highest point on the vertical straight section of pipe because, in my opinion, all that height of fluid weighs on the inlet ?). So, I used the Bernoulli law and calculate the condition for having an outlet speed > 0. The result is that Zs < Za + H (where Zs is the altitude of the outlet). Am I right? Because I have seen also in a video that the condition should be Zs < Za, with a classical flexible pipe. Thanks in advance.
ОтветитьThan you for the wonderful explanation!!! <3
ОтветитьSo, syphons wouldn't work in vacuum?
ОтветитьThanks for the physics refresher. Actually used it to drain a pool at home.
ОтветитьI still don't understand the definition of the "pressure" of the water that allows it to flow via a siphon.
Is it correct to assume that the reason it continues to flow is purely because of the possibility of a vacuum that causes the exiting water to always drag the adjacent water out until equilibrium between the exterior environment and the environment at the point of entry to the siphon?
Thanks a lot. I love physics when i umderstand it. You did the job 👍
ОтветитьThanks for making this video, its finally one that actually explains why this happens. Really appreciate it. :]
ОтветитьThank you ❤️
ОтветитьThanks from IND to UK ...
ОтветитьWater level “haiche”.
ОтветитьThis was really helpful, thank you!
ОтветитьThis was actually a terrible presentation by any standard
ОтветитьI just bought a jiggle siphon but couldn’t sustain the flow. Now I realise the hose needed to be filled first.
Ответитьyou did not speak about siphon you spoke about placing the siphon pipe in top of the water tank what if we put the siphon in the same location of the first example?
can we use the siphon as a valve when the pressure is high the water will go when the pressure is low the water will stay? you did not answer that
and siphon has S-shaped you did not drew that
Thank you so much
Ответитьsuper................
ОтветитьChrist. Thank you! It took like 5 videos before I found this one that didn’t just say “and then the water is sucked out”. WHY is the water sucked out. Finally someone actually answered, thank you.
Ответитьএটা বায়ু শূন্য স্থানে কাজ করে স্যার
Ответитьrubbish ....the siphon should extend to the bottom of the tank....idiot.
Ответить