Epsilon-delta limit definition 1 | Limits | Differential Calculus | Khan Academy

does anyone know what application do they use to draw the graphs?

sal is the best

Finally got it, date : 25 dec 2023 Christmas day and I'm here 🙂

Can epsilon value be greater than 1

thankyou pal

Thank you sir

how can i find the next lesson? the link doesn't work
btw thanks for existing😂❤

Amazing!

Oh. My. Gulay. This is very helpful, thank you Sir

So please correct me if my summarization/understanding is wrong here. In summary, the epsilon-delta definition says: if you give me any output range (ε, epsilon) about a limiting output ('L' in the video), I can always give you an input range (δ, delta) in which input values (i.e., x values) that are closer to my limiting input ('a' in the video) yield output values (i.e., y values) closer to my limiting output. That is, if the limit exists, given a range δ about 'a', x values within δ approaching 'a' will yield y values within ε approaching 'L'.

Best

time to update this video lol

In multi variable calc and need to revisit this definition, very helpful video thank you!!

understanding with a diagram is always better ...

I learned this in the second week of calculus i am so ready to drop out but I can't

Cheers to this video for uniting troubled calc students for over a decade.

Thank you soo much

HALA Madrid 🤍🤍🤍

I miss 2009

Why must epsilon be greater than 0

I cannot see what is being put on the screen

🇧🇩

Nice explanation, but your epsilons and deltas really s*ck! 😜

actually superb ,conception cleared😄😎

Got more from a 12 minute khan academy video than 1 hour of reading in the book, thank you!

OMG! I've watched so many videos and read books but didnt get this concept, thanks for explaining this in a easy way with graphs🛐

Ah yes, that good ol' 240p

old but gold

Ugh this s*** It’s just not clicking for me

Thanks alot Khan Academy for this video.

Why start with epsilon? The "translation" (to the statement involving mathematical notations) of "as x approaches a, f(x) approaches L" should be something like, "for every delta > 0 there exists an epsilon > 0, such that whenever |x-a|<0, |f(x) - L| < 0". Why start with epsilon? When f(x) (which is associated with epsilon) approaches L only after x approaches a.

Thank you so much for this

Bruh this is not legible

Still helping students in September 2021, thank you!

insane

Published in 2009 and saving my uni life in 2021. Thank you so much! XD

i watch kehan during the uni lectures

It's best to be very familiar with the language of inequalities to prove without a doubt that a limit exists for a function. We learn about inequalities early in algebra but by the time calculus rolls around we have forgotten inequalities. This is a good video to get an intuitive idea of a what a limit means, but the algebra of inequalities must be used to prove "without a doubt."

Thank youuuuu

I am a Chemistry first year student still I have it🤦🤦

Great Sir...,🙏

This is the best video I watched within this topic

Sir fir epsilon-delta and slope me kya difference h

Thank you!

God I'm so glad I was born in the 2000s, I have no idea what I would've done if I didnt have instant access to wonderful people like Sal