7 Riddles That Will Test Your Brain Power - Episode #6

Easier way for Riddle #1, without case analysis:
The 3 statements: >=1, <5, >=5
Since only one statement is true, and one of <5 and >=5 must be true. then >=1 must false.
That means # of coins cannot >=1, i.e. < 1. Then I have 0 coins.

i think u can fold the paper from the top half so that bottom of roman number would be six in roman form

Substract 3 from nine: ply the paper from top to halve of the IX and turn the paper upside down

Answer to prove right wing feminazis screaming misogyny is that Bob is a. Gentleman and let Alice win both races 😂

everyone is talking about what is already discussed in the video..but no one is answering the bonus 2 riddle....

4 or 9!

For Riddle 3, a bonus answer: Since the numerical system isn't specified, one can assume any suitable numerical system, for instance, Base33. in the Base33 numerical system, 10 is thirty-three (decimal) coins, meaning you simply place eleven (decimal) coins in each of the 3 glasses.

riddle 3 is kind of a joke

My solutions:
1-2: I got the solution
3: Nope
4: Only the "in" one, the "4" one is very funny.
5: I got the right answer but I overcomplicated it by actually trying to do the math.
6: Got stumped.
7: I got it.
Bonus 1: Nope
Bonus 2: Just do != (unequal)

Man, changing or inventing rules just because it isn't forbidden explicitely always feels like a bullshit way to solve these riddles. Sure just create an inequality sign and place one glass in another glass, why not just cut the coins in half, it's doesn't say you can't do that as well. Meh to me.

poor Bob 😂

10 to 10 = 9.50 its time

Bonus riddle 1:

I solved it without actually touching the pen. There’s a tape there, X is just two Vs mirrored together from top to bottom. You don’t need to use the pen. Use both the paper and the tape to halve the top half of IX, which is basically IV. Paste the tape on IV. Then turn the book 180 degrees. VI equals six. Wasn’t that hard. Yet Ammar said to draw an S at IX, which is basically lifting the pen, which is not allowed for not lifting the pen out of the paper to be a condition.

Often, in such puzzles, my background in analytic philosophy helps me. I disagree with the premises in the given problem. Generally, when we say we have fewer than five coins, we are suggesting that we have some coins in the first place. Otherwise, we would say we have no coins. The quality, or characteristic, of "having coins" means that we affirmatively HAVE coins. We may have any number of coins (or one coin) but to have zero coins is not to have the status of having coins, "fewer" or otherwise. Consider also that there are no cases in the English language where "a few" means none at all. If we say, "fewer and fewer men have coins these days", we do NOT mean that NO men have coins. Consider also that as stated, the problem could be interpreted to mean that people possess a property (say, a coin) of whose nature they were totally ignorant. For example, let's say your culture doesn't use coins, and you don't know what a coin is. Someone gives you a box with four non-coins in it (say it was four other objects you didn't know about), and you are asked what's in the box. Logically, you have no coins in the box, but you do not know what a coin is. Would you then be justified in saying you had "fewer than five coins"? Welcome to the uneasy mathematical relationship between zero and the empty set.

Didn't give us enough time to solve #7.

≠

Add a line on top of 2nd 1 of 10 makes 10 T0 10 equals 9.50

for the last one, just write 6 without lifting after I X

draw a slash onto the equal to sign. make it not equal to

for 3rd riddle even though we place one glass in other,we see each glass seperately and count no.of coins in each glass seperately,so what is the matter of keeping one glass in other

BONUS RIDDLE 2 101010 ==/== 9.50 By place one straight line to make the equal symbol to Not equal symbol ( both sides are unequal )😅🤪

I could be in debt and have -10000 coins.

You can also write 6 next to it. 1×6=6

Those riddles are du*b as f**k.

Put the line horizontal on =

Why people from india talk like they have a hot potato in their mouth?

0 coins

9/9

the coin and glass riddle is an incorrect solution by definition. The question states that " EACH " glass must contain an odd number of coins . Even if you put the glass with 4 coins INTO the glass with 3 coins , that first glass still contains an even number of coins. It doesn't matter where you put IT , it still contains an even number.

=!

Question 3 is BS, it specifically asks to put an odd number of coins in 3 glasses, nowhere are you given the indication you can combine the glasses, otherwise the answer is obvious. Also if you combine the glasses they don't become 1 glass so it's wrong.

pitiful

10 T0 10 = 9.50

10 10 10 ≠ 9.50 🙂

Your 1st riddle/puzzle is incomplete and confusing in the requirements. Your 2nd riddle breaks the rule of having odd coins in 3 glasses. Even if you have 4 or whatever even number in the bottom or even top inserted glass it breaks the rule you gave us to the riddle/puzzle where the odd number of coins in the glasses is the main exercise. Even though glass B is inside glass A, there are still an even number of coins in glass A.

i got all of these correct. and then i threw my couch across the living room with just my mind. i am a god now. i'm off to find a supervillain. be well.

The answer to the last riddle is using a straight line to make equal to non-equal)

The IX riddle my first solution was 1x6 as I and X can be used as 1 and Multi ( X ) so I just write 6 without lifting the pen from paper

Alice is a he

question 1 is ill-posed, you cannot have nothing; the question is a shitty play on words turned into math.

When you put something into a spinning wheel it tries to get to the centre. So there are no fields. No magnetic or electric. Structures are the positional dependency of spin. Similarly there are no imagery numbers Associated spin quantum of numbers. Why do numbers spin because of the base or symbols. The duality of nature is just a vector positive or negative relative. Light takes two planes because of the negative drag effect. Curvature of space is a relative drag momentum of light. Drag effect is always one third because of next to half. For sound it is about 70 meters per second.

On the bonus question, follow 3 steps:
a) lift up the pen and write nothing on the paper.
b) lay the pen down so that is crosses the IX horizontally leaving the bottom half of the IX exposed
c) walk around to the opposite side of the table and a VI is displayed above the pen

The answer of the last riddle
Just strike the equal sign to make it correct that10 10 10 is not equals to 9.50

really bad

A faster way to figure out the water barrel is to add all the barrels = 119 and then add the numbers 1+1+9=11. 11 is not dividable with 3 —> 119 is not dividable with 3. If you take off 2 (11-2=9) it is dividable with 3, which means the water barrel is a number dividable with 3 +2 (witch is only 20, 20-2=18). If you take away 20 from 119 the total of the milk barrels will be dividable with 3.
This makes it faster and easier to do quickly without writing it down.

If you add all separate numbers in a big number until yo have a number you can easily divide by 3 in your head you know if the big number is dividable with 3 or not. You can also split it up into sections to make it easier (and take away all 3s, 6s and 9s - since those obviously are dividable by 3). For example, is 264718305619437 dividable with 3?
1: take away 6, 3, 6, 9 and 3.
2: 2+4=6 (take away), 7 (save), 1+8=9 (take away), 5+1 (take away), 4+7=11 (save).
3: 7+11=18 (dividable with 3) —> 264718305619437 is dividable with 3.

Riddle 4: What does "one" mean in this case? Couldn't you take one matchstick, break it into two pieces and place them against two others to create a square (with parts of the unbroken sticks sticking out)? Then, you would have moved one, but placed its two parts. So, a small way of cheating?

1,3,6