Комментарии:
I would really appreciate it if u had a transcript of this. thx tho!
ОтветитьBrilliant tuitorial
Ответить49 minutes and didn't cover virtual ground, or in general how to power them
ОтветитьI am trying to repair A pioneer DJM-S9 and the schematics are not freely available. the balanced output has hot and cold left and right that goes through opamps and the cold outputs have fuses on them. Both fuses had blown for the left and right outputs and after replacing them I looked at the outputs and the hot has clipping on the left and right over a certain volume level. After watching this I kind of understand, but I am more confident with digital electronics so a little out of my comfort zone. If I remember the voltage for the +15 and -15v are ok and the hot and cold have the same peek to peek voltage as them come into the circuit. All advice so far is to just replace the £400 board that no one has for sale and I can't ask pioneer they will just not give any help..
ОтветитьAnyone got the answer for the last quiz?
Ответитьthank you for sharing your knowledge my good sir
ОтветитьI just read the other night in a book, or app note (I'll have to find which) that op-amps were initially developed by phone companies because their amplifiers had unstable gain trying to set it exactly. So insteady, they made an amplifier with entirely too much gain which you could adjust for the necessary application. Does anybody know how much, if any truth there is to this?
Ответитьgreat video, quick question does the feedback always feed back to the inverting side (negative input) of the OpAmp?
ОтветитьTest
ОтветитьHello Dave!
Can you please tell me the reason why Rf in the negative feedback circuit has to be greater than R1 in the case of non-inverting amplifier ?
Thank you for posting this video
Ответить@31m49s; Oops.. you are so cute!
ОтветитьSaved this one in applied science.
ОтветитьWhy thoese ripples at the end of the video ? Anyone can explain ?
ОтветитьYour video is gold. I modeled both inv amp and non-inv amp in LTspice with MAX4352 op-amp. Input voltage: [0,0.5] volts. Vcc:+5v, Vee: GND. Worked perfect. Thanks for your work!
ОтветитьIt’s being over 2 years now am still trying to understand how to get any op amp to work when I add vcc and end 12 volt am getting 12 volt on the output and half is 6 volt negative and 6 positive when I add 33 millivolt the positive voltage don’t get greater because the pnp it’s still on and npn is still am not getting anything of them to stay off am designing a current senor I can get the bjt to turn off even at 12 volt over current on the resistor the two transistor still on so i read the database sheet on I can find anything to staying the output is voltage is zero I use lpm 358 and ua741 op amp and o get the same results I can’t understand how it work in real time as a operation amplifier i use every ic knew to men but op amp is the one ic I can get to work in current sensor circuit only comparator work
Ответитьfirst 55 seconds of this video told the whole story, I kept asking WHY OP AMPS? and here it is in 55 seconds.
Ответитьi watched this with the biggest shit eating eureka grin on my face because it MAKES SENSE NOW
ОтветитьWireless
ОтветитьThank you ❤️
ОтветитьOups?!
ОтветитьHonestly, you need a bit of background and experience with them, then this summary is a good overview. But too abstract when you haven't seen it on a scope and tested it with various signals. Nice for memorizing though.
ОтветитьNine years later, this is still the best and most understandable intro to Op Amps ever.
ОтветитьDoes anyone know the answer to the last question he asks?
ОтветитьI watched this 3 months ago. I played with some opamps. Then I got burned out from all the study. Now I'm here again because I forgot what I learned before.
ОтветитьYou have saved me fr fr
ОтветитьThis is brilliant, mate! Thank you. I still have heaps to understand, but this is the best video I've seen on OpAmps, and I've watched a good number of them.
I've been trying to understand exactly what happens in the soft clipping stage of an OpAmp circuit in an overdrive pedal. Trying to understand signal flow, and how the opposing diodes affect things, etc. I still don't fully understand, but this video brings me closer. Thanks again.
Brilliant video thank you .But i send my condolences for looking a bit like Jeremy Hunt the UK chancellor of the Exchequer .
ОтветитьI was am A student in my EET school and did great w the math, understood digit TTL.... But when we got to analog chips like the Op Amp, I just couldn't grasp it w a gut intuition, and started to get behind the instructor, constantly playing catchup. I didn't have problems w the math, but since I didn't have that intuition I was just plugging in numbers and not understanding the fundamentals. I had no idea what the 741 was able to do, what it was for, and completely flummoxed when the amplifier circuits were combined w other chips and components.
When Dave started out by erasing that scary looking circuit and the math, I was like, ah ha! His method of starting w the basics got me thinking after 30 years, I'm finally gonna be able to comprehend this! For years, I was so intimidated by the 741 that I'd quickly become discouraged when circuits had them and I'd just give up and would just mindlessly follow the schematic and solder em in. Those days are coming to an end.
Thanks, Dave. If it weren't for Dave TV, grasping this would be a whole lot harder. Stand aside, Mr 741 Op Amp!
This is an excellent intro to Op Amps. Great work!
ОтветитьSimple and comprehensive
ОтветитьEight years later, this is still the best and most understandable intro to Op Amps ever.
ОтветитьYou're the man!
ОтветитьYou are a star!
ОтветитьA question after 8 yrs :If referencing that virtual ground node to positive or negative rail will make the input signal reappears on the scope ?
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Great teacher!
ОтветитьThank you Sir!!!!
ОтветитьWhy is it that he does a better job than my university :)
ОтветитьThanks for the fantastic video! One question in regards to offset: when the (+) input is set to half of V+, I get that the "virtual ground" becomes half of V+ following the rule 2. In this case though, why does this not affect the i(current) magnitude that goes through Ri and Rf change (or in other words, how does it offset the input signal)?
ОтветитьBecause of rule number 2,doesn't that mean that the two reasstors are connected in series ? and the current must equal 1/11ma ?
ОтветитьKisses from Germany ❤
Ответить"You can turn it into a summa which is just an adda!" 😄 I LOVE Oz... Thanks for a great vid!
ОтветитьThank you for the videos ☺️
ОтветитьHello world from Kashmir
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